Mumbai Indians posted a total of 235/9 in their 20 overs.© IPL
Mumbai Indians (MI) posted the highest total of the Indian Premier League (IPL) 2021 season when they scored 235/9 in their allotted 20 overs against Sunrisers Hyderabad (SRH) in Abu Dhabi on Friday. With skipper Rohit Sharma winning the toss and electing to bat – MI went into the match which needed a 170-plus run win to reach the playoffs – Ishan Kishan played a quick innings to lay the foundation for a big total. Kishan scored 84 off 32 balls before Suryakumar led the innings with a 40-ball 82 to take MI to the highest score by a team in the IPL 2021 season.
Kishan hit 11 fours and four sixes in his explosive innings while Suryakumar hit 13 fours and three sixes. Jason Holder was one of the SRH bowlers with figures of 4/52.
The previous highest team of the season was Punjab Kings’ 221/6 against Rajasthan Royals in April.
Earlier at the toss, Rohit said that considering the permutations and combinations to race for the playoffs, MI had no option but to bat first.
“We’re going to bat first, no option (smiles). The numbers are scary, but we’re going to give it our all. Let’s hope we can come out and do what we love to do.” It’s important to enjoy the game because it’s good. It’s been a season for us on and off. It’s a great opportunity for us to do something that has never been done before,” said Rohit.
MI had a net run rate of -0.048 prior to this game, which is why they face an almost impossible challenge of making the playoffs.
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